The zeros of this quadratic function are (D) x=7 and x=-8.
Quadratic function is a relation or expression in which highest power of the variable is 2.
Given the quadratic function is [tex]f(x)=(x-7)(x+8)[/tex]
So the zeros are found by solving [tex]f(x)=0[/tex].
On solving [tex]f(x)=0[/tex] we get,
[tex](x-7)(x+8)=0[/tex]
We know that if the product of two mathematical expression is zero then at least one of them is zero.
Either, [tex]x-7=0\Rightarrow x=7[/tex]
Or, [tex]x+8=0\Rightarrow x=-8[/tex]
Hence the zeros for the given quadratic function [tex]f(x)=(x-7)(x+8)[/tex] are [tex]x=7[/tex] and [tex]x=-8[/tex].
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