Question

The length of a rectangle is eight more than twice it’s width. The perimeter is 88 feet. Find the dimensions of the rectangle.

Answer 1

Answer:

Length = 32 feet

Width = 12 feet

Step-by-step explanation:

The length of a rectangle is eight more than twice its width.

The perimeter is 88 feet.

Let's say the width (w) is x feet

The length (l) will be 2x + 8

Perimeter of a rectangle = 2l + 2w

So 2(2x + 8) + 2x = 88

4x + 16 + 2x = 88

6x + 16 = 88

6x = 88 - 16

6x = 72

x = 12

So the width is 12 feet.

The length is 2(12) + 8 = 32 feet

Answer 2

The dimensions are 12 feet and 32 feet.

Let the width of the rectangle = w

Length = (2 × w) + 8 = 2w + 8

Perimeter = 88 feet

Then, the equation to solve the dimensions will be:

Perimeter = 2l + 2w

88 = 2(2w + 8) + 2(w)

Collect like terms

88 = 4w + 16 + 2w

4w + 2w = 88 - 16.

6w = 72

w = 72/6 = 12

The width is 12 feet

The length will be:

= 2w + 8 = 2(12) + 8 = 24 + 8 = 32

The length is 32 feet

Therefore, the dimensions are 12 and 32 feet.

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