An ac series circuit has an impedance of 192 Ω, and the phase angle between the current and the voltage of the generator is ϕ = −75°. The circuit contains a resistor and either a capacitor or an inductor. Find the resistance R and the capacitive reactance XC or the inductive reactance XL, whichever is appropriate.

Respuesta :

Answer:

Resistance = 49.69 ohm

Capacitive reactance / inductive reactance = 185.45 ohm

Explanation:

We have given impedance of the circuit = 192 ohm

Angle between voltage and current [tex]\Phi =-75^{\circ}[/tex]

Power factor [tex]=cos(-75^{\circ})=0.2588[/tex]

We know that power factor is given by [tex]cos\Phi =\frac{R}{Z}[/tex]

[tex]0.2588=\frac{R}{192}[/tex]

[tex]R=49.693ohm[/tex]

Impedance is given by [tex]Z=\sqrt{R^2+(X_L/X_C)^2}[/tex]

[tex]192=\sqrt{49.693^2+(X_L/X_C)^2}[/tex]

Squaring both side [tex]36864=2469.419+(X_L/X_C)^2[/tex]

[tex]X_L/X_C=185.457ohm[/tex]

The resistance R and the capacitive reactance XC or the inductive reactance XL is mathematically given as

  • R=49.7
  • X_L/X_C=185.457ohm

Question Parameters:

An ac series circuit has an impedance of 192 Ω,

the current and the voltage of the generator is ϕ = −75°.

given power factor to be 0.2588

and

[tex]cos\phi =\frac{R}{Z}\\\\0.2588=\frac{R}{192}[/tex]

R=49.7

Generally the equation for the Impedance   is mathematically given as

[tex]Z=\sqrt{R^2+(X_L/X_C)^2}[/tex]

Therefore

[tex]192=\sqrt{49.693^2+(X_L/X_C)^2}[/tex]

X_L/X_C=185.457ohm

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