Imagine you have m distinct baskets in which you’re throwing n number of balls at random. Each throw is independent of any other throw, and every basket is equally as likely to get a ball on a throw. After the n throws, what is the probability that a given basket is empty?

Respuesta :

Answer:

[tex](\frac{m-1}{m})^n[/tex]

Step-by-step explanation:

Given a basket, the probability of a ball to end there is [tex]\frac{1}{m}[/tex] (because there are m baskets).

Then, the probability of a ball to end in other basket is [tex]\frac{m-1}{m}[/tex].

Finally, the probability of the basket to remain empty after n throws is

[tex](\frac{m-1}{m})^n[/tex]

This last is because, given n independets events with probability p, the probability for all of them to happen is [tex]p^n[/tex]. In this case [tex]p=\frac{m-1}{m}[/tex]

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