I2 is produced by the reaction of 0.4235 mol of CuCl2 according to the following equation: 2CuCl2+4KI 2CuI+4KCl+I2

Respuesta :

Answer:

React with 0.847 mol of KI

Produce:

0.4235 mol of CuI

0.847 mol of KCl

0.21175 moles de I2

Explanation:

2CuCl2 + 4KI    produce 2CuI + 4KCl  + I2

The stoichiometric coefficients give us the relationship in moles:

2 mol of CuCl2 ....react whit....4 mol of KI

0.4235   mol of CuCl2 ....react whit...X=   0.847mol of KI

2 mol of CuCl2 ....produce....2 mol of CuI

0.4235   mol of CuCl2 ....produce....X=0.4235 mol of CuI

2 mol of CuCl2 ....produce....4 mol of KCl

0.4235   mol of CuCl2 ....produce....X= 0.847 mol of KCl

2 mol of CuCl2 ....produce.... 1 mol of I2

0.4235   mol of CuCl2 ....produce....X= 0.21175 moles de I2

If you need to know the mass that is produced you just have to multiply the moles by the molecular mass

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