Question

A body of mass 9 kg moves in a (counterclockwise) circular path of radius 8 meters, making one revolution every 8 seconds. You may assume the circle is in the xy-plane, and so you may ignore the third component. A. Compute the centripetal force acting on the body.

Answer 1

Answer:

centripetal Force$=44.36\ \rm N$

Explanation:

Given:

Mass of the body $m=9\ \rm kg$

Radius of the circle $R=8\ \rm m$

Time period $T=8\ \rm s$

The centripetal Force acting on the body is given by F

$F=\dfrac{4\pi^2 m R}{T^2}\\F=\dfrac{4\pi^2\times 9\times8}{8^2}\\F=44.36\ \rm N$

Hence the centripetal force acting on the body is calculated