Question

NEED ASAP
The fair spinner shown is spun 2 times. The set of possible outcomes are: S = {RR, BB, YY, GG, RB, BR, RY, YR, RG, GR, BY, YB, BG, GB, YG, GY} The number of yellows in the outcome is summarized in the table on the right. Using the data from the theoretical probability table, what is the probability of the spinner landing only once on yellow in two spins?
a. 0.0625
.0.5625
c.0.375
d.1

Answer 1

Answer:

C

Step-by-step explanation:

Answer 2

The probability of the spinner landing only once on yellow in two spins is P = 0.375

How to get the probability?

All the possible outcomes have the same probability, so, the probability that in two spins the spinner land only once in yellow is given by the quotient between the number of outcomes that have only one yellow and the total number of outcomes.

All the outcomes are:

{RR, BB, YY, GG, RB, BR, RY, YR, RG, GR, BY, YB, BG, GB, YG, GY}

16 in total.

The ones where the spinner lands only once on yellow are:

{RY, BY, YB, YG, GY, YR}

6 outcomes.

So the probability is:

P = 6/16 = 0.375

If you want to learn more about probability, you can read:

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