Answer:
The separation of the 2 points should be 50.0 meters.
Explanation:
According to Rayleigh's scattering criteria the angular separation between 2 points to be resolved equals
[tex]\theta =1.22\cdot \frac{\lambda }{D}[/tex]
Applying the given values we get
[tex]\theta =1.22\cdot \frac{550\times 10^{-9} }{5.1}=0.1316\times 10^{-6}rads[/tex]
thus the linear separation equals [tex]L=\theta \times Distance[/tex]
Applying the given values we get
[tex]L=0.1316\times 10^{-6} \times 3.8\times 10^{5}\times 10^{3}meters\\\\\therefore L=50.00metes[/tex]