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A building superintendent twirls a set of keys in a circle at the end of a cord. If the keys have a centripetal acceleration of 114 m/s2 and the cord has a length of 0.29 m, what is the tangential speed of the keys? Answer in units of m/s.

Respuesta :

Pot8o

Answer:

5.75m/s

Explanation:

The formula we need to use here is the formula of centripetal acceleration given as

[tex]a=v^{2} /r[/tex]

we have the acceleration and the radius (luckly in the units we need them to be)

replacing it would yield

[tex]114m/s^{2} =v^{2} /0.29m[/tex]

then solving for v

[tex]\sqrt{114m/s^{2} * 0.29m }= v[/tex]

[tex]\sqrt{33 m^{2} / s^{2}}= v\\ 5.75 m/s = v[/tex]

(notice how m/[tex]s^{2}[/tex] * m yields [tex]m^{2}/s^{2}[/tex] which when applying the square root yield m/s)

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