Answer:
Step-by-step explanation:
Given that a marketing research firm is estimating which of two sodas (A or B) college students prefer.
Sample size of 75 was taken at random.
Since sample size is sufficiently large i.e. >30, and also since samples are taken at random, we can assume that sample proportion
p= [tex]\frac{45}{75} =0.6[/tex] follows a normal distribution with mean = 0.6 and variance = npq = 75(0.6)(0.4)
Yes, this sample is large enough to calculate a confidence interval.
