Find the x- and y- intercepts of the following equation.

-3x + 4y = -12

y - intercepts : (0,4)
x - intercepts : (-3,0)

y - intercepts : (0,-6)
x - intercepts : (-3,0)

y - intercepts : (0,-6)
x - intercepts : (-4,0)

y - intercepts : (0,-3)
x - intercepts : (4,0)

Respuesta :

Answer:

The x-intercept is [tex](4,0)[/tex]

The y-intercept is [tex](0,-3)[/tex]

Step-by-step explanation:

Suppose you have a function f:

[tex]f = f(x,y) = 0[/tex]

The x-intercept is the value of x when [tex]y = 0[/tex].

The x-intercept is the value of y when [tex]x = 0[/tex].

Solution

We have:

[tex]f(x,y) = -3x + 4y = -12[/tex]

[tex]-3x + 4y + 12 = 0[/tex]

x-intercept

The x-intercept is the value of x when [tex]y = 0[/tex]. So:

[tex]-3x + 4(0) + 12 = 0[/tex]

[tex]-3x + 12 = 0[/tex]*(-1)

[tex]3x - 12 = 0[/tex]

[tex]3x = 12[/tex]

[tex]x = \frac{12}{3}[/tex]

[tex]x = 4[/tex]

The x-intercept is [tex](4,0)[/tex]

y-intercept

The y-intercept is the value of y when [tex]x = 0[/tex]. So:

[tex]-3(0) + 4y + 12 = 0[/tex]

[tex]4y + 12 = 0[/tex]

[tex]4y = -12[/tex]

[tex]y = \frac{-12}{4}[/tex]

[tex]y = -3[/tex]

The y-intercept is [tex](0,-3)[/tex]

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