Question

Which equation shows a slope of -5 and a y-intercept of (0,1) ?


y = -1x - 5

y = -5x + 1

y = 1x - 5

y = 5x = 1

Answer 1

Answer:

The equation that represents a slope of -5 and y-intercept of (0,1) is:

$f(x) = -5x + 1$

Step-by-step explanation:

The equation of a line can be described by a first order equation in the following format:

$f(x) = ax + b$

In which a is the slope of the line and b is the y-intercept.

Solution:

The problem states that the slope is -5, so:

$a = -5$

y intercept is (0,1), so

$b = 1$

The equation that represents a slope of -5 and y-intercept of (0,1) is:

$f(x) = -5x + 1$

Why the others are wrong?

$y = -1x - 5$

Here, the slope is -1, and the y-intercept is (0,-5).

$y = 1x-5$

For this option, the slope is 1 and the y-intercept is (0,-5).

$y = 5x - 1$

Is it 5x - 1? If so, the slope is 5, and the y-intercept is (0,-1).