Question

Find the slope of the line tangent to the graph of y = 2x3 – 2x + 57 at (–2, 45).

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Answer 1

Answer:

The slope = 22.

Step-by-step explanation:

First we find the derivative:

y' = 6x^2 - 2  

This gives the slope of the line tangent to the point (x, y) on the graph of y.

So for the tangent at (-2, 45) the slope is:

6(-2)^2 - 2 =  24 - 2

=  22.

Answer 2

Answer:

The slope is 22

Step-by-step explanation: