Answer:
9.209×10^{-5} gm.
Explanation:
Given: Length of the cylinder l= 28.0 mm
diameter of the cylinder d= 0.100 mm = radius r = 0.05 mm
The volume of the cylinder is given by V= [tex]\pi\times r^2\times l[/tex]
also, the density of the prostate generally is 419.3 kg/m^3
which is equal to = 0.4193 g/cm^3
mass= volume×density
mass= 0.4193×pi×r^2×l
mass= [tex]0.4193\times\pi\times2.8\times0.005^2[/tex]
= 9.209×10^{-5} gm.
the total mass of the tissue in grams = 9.209×10^{-5} gm.
