Answer:
y=\left(\frac{1}{9}\right)x^2+\left(\frac{4}{3}\right)x+3
or
y=(1/9)x^2+(4/3)x+3
Step-by-step explanation:
let equation be:
ax^2+bx+c=y
(-9) as root:
81a-9b+c=0 -(1)
(-3) as root:
9a-3b+c=0 - (2)
Pass (-6,-1):
36a-6b+c=-1 - (3)
(2)+(3)
45a-9b+2c=-1 - (4)
(1)-(4)
36a-c=1
c=36a-1 -(5)
from (3)
c=-1+6b-36a -(6)
from (5) & (6)
36a-1=-36a+6b-1
72a=6b
12a=b -(7)
(5) & (7) into (2)
9a-3(12a)+36a-1=0
9a=1
a=1/9 -(8)
from (7) & (8)
b=4/3
from (5) & (8)
c=3
answer:
y=(1/9)x^2+(4/3)x+3
