Answer:
The probability that the HR director will select an employee who is not a multiple of 13 is [tex]\frac{47}{50}[/tex]
Step-by-step explanation:
* Lets explain how to solve the problem
- The probability of an event is the measure of the chance that the
event will occur
- The probability of an event A is the number of ways that event A can
occur divided by the total number of possible outcomes
- If P(A) is the probability of event A, is the probability that the event A
does not occur is 1 - P(A)
* Lets solve the problem
- An HR director numbered employees 1 through 50 for an extra
vacation day contest
∴ There are 50 employees
- The HR director will select an employee
- We need to find the probability of select an employees who is not
multiple of 13
* At first lets find the multiples of 13
∵ 13 × 1 = 13
∵ 13 × 2 = 26
∵ 13 × 3 = 39
∴ The multiples of 13 from 1 to 50 are 13 , 26 , 39
∵ There are 3 multiples of 13
∵ There are 50 numbers
∵ Probability of multiple of 13 = [tex]\frac{3}{50}[/tex]
∵ Probability of not multiple of 13 = 1 - P(multiple of 13)
∴ Probability of not multiple of 13 = [tex]1-\frac{3}{50}[/tex]
∴ Probability of not multiple of 13 = [tex]\frac{47}{50}[/tex]
* The probability that the HR director will select an employee who is
not a multiple of 13 is [tex]\frac{47}{50}[/tex]
