Answer:
So X has an atomic mass of 55.05 u, and is probably Mn
Explanation:
Step1: Balance the equation
XI2 +Cl2 → XCl2 + I2
Step2: find the molar mass of the compounds
Compounds :
X ⇒ Molar mass = M
XI2 ⇒ Molar mass = M + 2*126.9 u
XCl2 ⇒Molar mass = M + 2*35.45u
⇒For 1 mole XI2 we have 1 mole Cl2 reacting , as well as 1 mole XCl2 and 1 mole I2 produced.
Step 3: Calculating the atomic mass
(1.383g * XI2) / (M + 2*126.90 u) = (0.564g * XCl2) / ( M + 2 * 35.45u)
1.383 (M + 2 *35.45 u )= 0.564 (M + 2*126.90)
1.383M + 98.0547 = 0.564 M + 143.1432
1.383 M - 0.564 M =143.1432 - 98.0547
0.819 M = 45.0885
M = 55.05 u
So X has an atomic mass of 55.05 u ⇒ if we look at the periodic table we can find that the closest element is Manganese (Mn)
MnI2 + Cl2 → MnCl2 + I2
