Question

Find the sum of (3x2 + 16x + 9) and (−16x − 12).

Answer 1

Answer:

$3x^2-3$

Step-by-step explanation:

We have $(3x^2 + 16x + 9) + (-16x - 12)$

To figure out the sum, you need to add like terms.

It would look like this:

$3x^2 + 16x - 16x + 9 - 12$

=$3x^2-3$