Question

The distance between (-6,-5) and (2,0)

Answer 1

Answer:

Step-by-step explanation:

You should use the distance formula:

√(2-(-6) squared + 0 - (-5) squared

8 squared + 5 squared = 64+25 = √89

The answer is approximately 9.433

Answer 2

Two points on a plane are separated by the distance between them. It is possible to calculate the distance between these points. The distance between (-6,-5) and (2,0) is 9.43 units

Given that:

$(x_1,y_1) = (-6,-5)$

$(x_2,y_2) = (2,0)$

The distance (d) between two points is calculated as:

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

So, we have:

$d = \sqrt{(-6-2)^2 + (-5-0)^2}$

$d = \sqrt{(-8)^2 + (-5)^2}$

$d = \sqrt{64 + 25}$

$d = \sqrt{89}$

Take square roots:

$d = 9.43$

Hence, the distance between  (-6,-5) and (2,0) is 9.43 units

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