Question

Determine the axis of symmetry for the function f(x) = 5(x + 1)2 − 8.

x = −8
x = 8
x = −1
x = 1

Answer 1

Answer:

C. $x=-1$

Step-by-step explanation:

We have been given a function formula $f(x)=5(x+1)^2-8$. We are asked to find the axis of symmetry for the given function.

We can see that our given function is a parabola in vertex form. We know that vertex from of parabola is $y=a(x-h)^2+k$, where (h,k) represents vertex of parabola.

Let us convert our given function in vertex form as:

$f(x)=5(x-(-1))^2-8$

We know that axis of symmetry of a parabola is the equation of x-coordinate of vertex, which in form $x=h$.

Since the x-coordinate of vertex is $-1$, therefore, the axis of symmetry for the given function would be $x=-1$.