Question

A bag contains 6 blue marbles, 4 red marbles, and 2 yellow marbles. What is the probability of selecting a blue marble, replacing it, then selecting another blue marble?

Answer 1

i think there is a .5 percent chance i added all numbers and divided by 6[the blue marbles]

Answer 2

Probabilities are used to determine the chances of an event.

The probability of selecting 2 blue marbles (with replacement) is 1/4

The given parameters are:

$\mathbf{Blue = 6}$

$\mathbf{Red = 4}$

$\mathbf{Yellow = 2}$

The total number of marbles is:

$\mathbf{n =Blue + Red + Yellow }$

$\mathbf{n =6 + 4 + 2}$

$\mathbf{n =12}$

The probability of selecting 2 blue marbles (with replacement) is:

$\mathbf{Pr = \frac{Blue}{n} \times \frac{Blue}{n}}$

$\mathbf{Pr = \frac{6}{12} \times \frac{6}{12}}$

Simplify

$\mathbf{Pr = \frac{1}{2} \times \frac{1}{2}}$

Multiply

$\mathbf{Pr = \frac{1}{4}}$

Hence, the probability of selecting 2 blue marbles (with replacement) is 1/4

Read more about probabilities at:

https://brainly.com/question/11234923