The answer is Gay-Lussac’s law.
Let's express all of these laws, using constant k, pressure P, temperature T, and volume V:
Boyle's law: PV = k
Charles law: V = kT
Dalton’s law: P = P₁ + P₂ + P₃ + ...
Gay-Lussac’s law: PV = kT
So, the only law that includes both pressure P and temperature T of a gas is Gay-Lussac’s law. We can check this hypothesis by using fictive values for each member of an equation.
For example, if
P₁ = ?
V = 6
k = 3
T₁ = 4
then P₁V = kT₁
⇒ P₁×6 = 3×4
⇒ P₁ = 12÷6
⇒ P₁ = 2
When we double the temperature:
T₂ = 2×T₁
⇒ T₂ = 2×4
⇒ T₂ = 8
Then:
P₂V = kT₂
⇒ P₂ × 6 = 3 × 8
⇒ P₂ = 24 ÷ 6
⇒ P₂ = 4
If P₂/P₁ = 4/2 = 2, this means that doubling temperature will double the pressure of the gas.
