Question

A low-power microprocessor consumes 5 mA at DC. How many electrons flow through the power wiring per second?

Answer 1

Answer:

Explanation:

time, t = 1 second

i = 5 mA = 0.005 A

Charge of one electron, e = 1.6 x 10^-19 C

Charge, q = i t

q = 0.005 x 1 = 0.005 C

Number of electrons in one second = total charge / charge of one electron

$\frac{0.005}{1.6 \times 10^{-19}}=3.125 \times 10^{16}$