Question

Unpolarized light passes through two polarizers; the axis of one is vertical and that of the other is at 54.0 o to the vertical. What is the ratio of the transmitted light intensity to the original light intensity?

Answer 1

Answer:

0.3455

Explanation:

Using Malus law as:

$I=I_0\times cos^2\ \theta$

Where,

$I=$ is the intensity of the transmitted light

$I_0$ is the intensity of the incident light

$\theta$ is the angle between the polarizer.

Given that:

$\theta=54.0^0$

To find the ratio of the transmitted light intensity to the original light intensity which is $\frac {I}{I_0}$

So,

$\frac {I}{I_0}=cos^2\ 54^0=0.3455$