Question

A cylinder which is in a horizontal position contains an unknown noble gas at 52600 Pa and is sealed with a massless piston. The piston is slowly, isobarically moved inward 0.150 m, while 18600 J of heat is removed from the gas. If the piston has a radius of 0.305 m, calculate the change in internal energy Δ???? of the system. Δ???? = _______J

Answer 1

Answer:-16.3 kJ

Explanation:

Given

Pressure inside Cylinder=52,600 Pa

Piston Moved Slowly inwards 0.15 m

Area of piston(A)$=\frac{\pi }{4}d^2$

$A=0.2922 m^2$

Change in volume=A\Delta L[/tex]

$\Delta V=0.292\times 0.15=0.04384 m^3$

Heat removal=18,600 J

From First Law of thermodynamics

$\Delta U=Q-W$

$W=P\Delta V$

$W=52600\times 0.04384=-2.3061 kJ$

as volume is decreasing

Q=-18.6 kJ

$\Delta U=-18.6+2.3061$

$\Delta U=-16.29 \approx 16.3 kJ$