Question

Calculate the mean effective load (in kN) on a ball bearing (p=3) under varying loads with a dynamic load rating of 36.8 kN and a predicted life of 90x10^6 of revolutions (tip L is expressed in millions of revolutions).

Answer 1

Answer:

The mean effective load (in KN) =8.21 KN

Explanation:

Given that

Dynamics load rating C= 36.8 KN

$life\ of\ bearing\ L_{MR}=90\times 10^6$

We know that life of bearing in million revolutions is given as follows

$L_{MR}=\left(\dfrac{C}{P_e}\right)^p$

Given that bearing is ball bearing so here we will put p=3

$L_{MR}=\left(\dfrac{C}{P_e}\right)^3$

Now by putting the values

$90=\left(\dfrac{36.8}{P_e}\right)^3$

$P_e=8.21 KN$

So the mean effective load (in KN) =8.21 KN