Question

The rectangular coils in a 345-turn generator are 12 cm by 12 cm. Part A
What is the maximum emf produced by this generator when it rotates with an angular speed of 505 rpm in a magnetic field of 0.45 T ? Express your answer using two significant figures.

Answer 1

Answer:

118.166 volt

Explanation:

We have given number of turns N =345

Sides of the rectangular coils is 12 cm =0.12 m

So area A =0.12×0.12=0.0144 $m^2$

Magnetic field B =0.45 T

Angular speed =505 rpm

Speed in rad/sec $\omega =\frac{2\pi N}{60}=\frac{2\times 3.14\times 505}{60}=52.8566rad/sec$

The emf is given by $E=NAB\omega SIN\omega t$

For maximum emf sinwt =1

So $E=345\times 0.0144\times 0.45\times 52.8566=118.166volt$