Question

As measured in Earth's frame of reference, two planets are 384000 km apart. A spaceship flies from one planet to the other with a constant velocity, and the clocks on the ship show that the trip lasts only 1.02 s. How fast is the ship traveling?

Answer 1

Answer:

Explanation:

   Time dilation formula is as follows

$T_1=\frac{T}{\sqrt{1-\frac{v^2}{c^2} } }$

T₁ is time observed by stationary observer and T is time recorded by moving clock.

Given T = 1.02 and

T₁ = 3.84 X10⁸ / v [ Let v be velocity of spaceship as observed by observer on earth ]

Putting these values in the time dilation formula

3.84 x 10⁸ / v = \frac{1.02}{\sqrt{1-\frac{v^2}{9\times10^{16}} } }[/tex]

v = 2.345 x 10⁸ ms⁻¹