A platform oscillates in the vertical direction with SHM. Its amplitude of oscillation is 0.20 m. What is the maximum frequency (Hz) of oscillation for a mass placed on the platform to remain in contact with the platform?

Respuesta :

Answer:

1.115 Hz

Explanation:

We have given amplitude of the oscillation a=0.20 m

Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]

The maximum frequency of the oscillation is given by [tex]f_{max}=\frac{1}{2\pi }\sqrt{\frac{g}{a}}=\frac{1}{2\times 3.14}\sqrt{\frac{9.81}{0.2}}=1.115 Hz[/tex]

So the maximum frequency of the oscillation is 1.115 Hz

Answer:

Maximum frequency =[tex]f_{max}= 1.115[/tex] [tex]Hz[/tex]

Explanation:

Given amplitude=A=0.20 m

Gravitational acceleration=9.81 [tex]m/s^{2}[/tex]

Using equation of maximum frequency we have

[tex]f_{max}=(1/2\pi)*\sqrt{g/A} \\[/tex]

substitute values,

[tex]f_{max}=(1/2*3.14)*(\sqrt{9.82/0.20}[/tex]

Maximum frequency=[tex]f_{max}=1.115[/tex] [tex]Hz[/tex]

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