Question

A convex mirror has a radius of curvature of 0.60 m. Where must an object be placed in front of the mirror such that the image is formed 0.25 m behind the mirror?

Answer 1

Answer:

1.5 cm

Explanation:

radius of curvature, R = + 0.60 m

focal length = half of radius of curvature = 0.60 / 2 = + 0.30 m

distance of image from the mirror, v = + 0.25 m

Let the distance of object from the mirror is u.

Use the mirror formula

$\frac{1}{f}=\frac{1}{v}+\frac{1}{u}$

$\frac{1}{0.3}=\frac{1}{0.25}+\frac{1}{u}$

$\frac{1}{0.3}-\frac{1}{0.25}=\frac{1}{u}$

$\frac{0.25-0.3}{0.3\times 0.25}=\frac{1}{u}$

$\frac{-0.05}{0.075}=\frac{1}{u}$

u = - 1.5 cm

Thus,t the object is placed on the left side of mirror at a distance 1.5 cm .