Suppose you want to operate an ideal refrigerator with a cold temperature of −11°C, and you would like it to have a coefficient of performance of 6.30. What is the hot reservoir temperature (in °C) for such a refrigerator?

Respuesta :

Answer:

The temperature of hot reservoir is 30.58 degrees Celsius.

Explanation:

It is given that,

Temperature of the cold reservoir, [tex]T_c=-11^{\circ}C=-11+273=262\ K[/tex]

Coefficient of performance, [tex]CP=6.3[/tex]

We need to find the temperature of hot reservoir for such a refrigerator. The coefficient of performance is given by :

[tex]CP=\dfrac{T_c}{T_h-T_c}[/tex]

[tex]T_h[/tex] is the temperature of hot reservoir

[tex]T_h-T_c=\dfrac{T_c}{CP}[/tex]

[tex]T_h=\dfrac{T_c}{CP}+T_c[/tex]

[tex]T_h=\dfrac{262}{6.3}+262[/tex]

[tex]T_h=303.58\ K[/tex]

or

[tex]T_h=30.58^{\circ}C[/tex]

So, the temperature of hot reservoir is 30.58 degrees Celsius. Hence, this is the required solution.

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