Answer:
The temperature of hot reservoir is 30.58 degrees Celsius.
Explanation:
It is given that,
Temperature of the cold reservoir, [tex]T_c=-11^{\circ}C=-11+273=262\ K[/tex]
Coefficient of performance, [tex]CP=6.3[/tex]
We need to find the temperature of hot reservoir for such a refrigerator. The coefficient of performance is given by :
[tex]CP=\dfrac{T_c}{T_h-T_c}[/tex]
[tex]T_h[/tex] is the temperature of hot reservoir
[tex]T_h-T_c=\dfrac{T_c}{CP}[/tex]
[tex]T_h=\dfrac{T_c}{CP}+T_c[/tex]
[tex]T_h=\dfrac{262}{6.3}+262[/tex]
[tex]T_h=303.58\ K[/tex]
or
[tex]T_h=30.58^{\circ}C[/tex]
So, the temperature of hot reservoir is 30.58 degrees Celsius. Hence, this is the required solution.