Answer:
4.001805 amu
Explanation:
931 Mev = 1 amu
28 Mev = 28 / 931 Mev
= .030075 amu
Helium nucleus consists of 2 proton and 2 neutron .
Binding energy in terms of amu
= total mass of 2 neutron and 2 proton - mass of nucleus of helium
mass of nucleus of helium = total mass of 2 neutron and 2 proton -Binding energy in terms of amu
mass of 2 neutron = 2 x 1.008664 = 2.017328
mass of 2 proton = 2 x 1.007276 = 2.014552
total = 4.03188
So mass of helium nucleus = 4.03188 - .030075
= 4.001805 amu.
