Answer:
Final temperature of the gas = -146.63 °C
Explanation:
At constant pressure, volume and temperature of the gases are related as:
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
Where,
V1 = Initial volume = 1.00 L
V2 = Final volume = 2.40 L
T1 = Initial temperature = 30.5 °C = 30.5 + 273.15 = 303.65 K
Now, substitute the values in the above equation,
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
[tex]\frac{2.40\;L}{303.65}=\frac{1.00\;L}{T_2}[/tex]
[tex]T_2=\frac{1.00\times 303.65}{2.40}[/tex]
T2 = 126.52 K
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
T( °C) = T(K) - 273.15
= 126.52 - 273.15 = -146.63 °C
