Answer: 0.57
Step-by-step explanation:
Given : The speed of cars on a stretch of road is normally distributed .
Population Mean = [tex]\mu=51\text{ miles per hour}[/tex]
Standard deviation : [tex]\sigma= 5.9\text{ miles per hour}[/tex]
Let x be the random variable that represents the speed of cars on a stretch of road .
z-score : [tex]z=\dfrac{x-\mu}{\sigma}[/tex]
For x= 50.
[tex]z=\dfrac{50-51}{5.9}\approx-0.17[/tex]
By using the standard normal distribution table ,
The probability that a randomly selected car is violating the speed limit of 50 miles per hour :-
[tex]P(x>50)=1-P(x\leq50)=1-P(z\leq-0.17)\\\\=1- 0.4325051=0.5674949\approx0.57\\[/tex]