Answer:
1680
Step-by-step explanation:
We have "AAABBBCCC" in this word there 3A ,3B and 3C
We have to calculate the number of distinguishable permutation
Here total number of character = 9
So total number of permutation =9!
A is repeated 3 times so permutation of A = 3!
B Is repeated 3 times so permutation of B=3!
C Is repeated 3 times so permutation of C=3!
So total number of distinguishable permutation [tex]=\frac{9!}{3!3!3!}=1680[/tex] (as when we find the distinguishable permutation then we have to divide with the permutation of the repeated character)
