Question

Given a 1.25 µF capacitor, a 5.25 µF capacitor, and a 9.00 V battery, find the charge on each capacitor if you connect them in the following ways.
(a) in series across the battery
µC

(b) in parallel across the battery

1.25 µF capacitor µC
5.25 µF capacitor µC

Answer 1

Answer

a ) 9 μC

b )11.25 μC , 47.25 μC

Explanation

When two capacitor 1.25 μF and 5.25  μF are joined in series , total capacitor is calculated below

a ) C (Total ) = $\frac{1.25\times5.25}{1.25+5.25}$

= 1 μF

Charge in the circuit

=Potential x capacitance

= 1 x 9 = 9 μC. Each of the capacitor will have this charge.

b ) Charge across 1.25 capacitor = 1.25 x 9 = 11.25 μC

Charge across 5.25 capacitor = 5.25 x 9 = 47.25 μC