Question

leticia spent $11.19 on a bag of blue and red candy and the bag weighed 11 pounds if the red candy coast $1.29 per pound and the blue candy coast $0.79 per pound how much of each candy did she buy ?

Answer 1

Answer:

[b, r] → [$5, $6]

Step-by-step explanation:

{11 = r + b

{11,19 = 1,29r + 0,79b

-1,2658227848[11,19 = 1,29r + 0,79b]

{11 = r + b

{-14,164556962 = -1,6329113924r - b

________________________________________

-3,164556962 = -1,6329113924r

______________ ________________

-1,6329113924 -1,6329113924

6 ≈ r [Plug this back into both equations to get an approximate b-value of 5]; 5 ≈ b

I hope this helps you out alot, and as always, I am joyous to assist anyone at any time.

Answer 2

The required pounds of the red and blue candy is 6 and 5 pounds respectively.

leticia spent $11.19 on a bag of blue and red candy and the bag weighed 11 pounds if the red candy cost $1.29 per pound and the blue candy cost $0.79 per pound how much of each candy did she buy is to determined.

What is equation?

equation is the relationship between variable and represented as y = ax+c   is example of polynomial equation.

Let the numbner of red candy is r and blue candy is b,
The bag weighed 11 pounds
r + b = 11 - - - - - (1)

the red candy coast $1.29 per pound and the blue candy coast $0.79 per pound leticia spent $11.19 on a bag.
1.29r + 0.79b = 11.19  - - - - - -(2)

From equation 1
r = 11 - b
Put r in equation 2
1.29 (11-b) + 0.79b = 11.19
b = 6
Put b in equation 1
r + 6 = 11
r = 5

Thus, the required pounds of the red and blue candy is 6 and 5 pounds respectively.

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