Question

A beam of light travels from a medium with an index of refraction of 1.27 to a medium with an index of refraction of 1.46. If the incoming beam makes an angle of 14.0° with the normal, at what angle from the normal will it refract?

Answer 1

Answer:

12.15°

Explanation:

Using Snell's law as:

$n_i\times {sin\theta_i}={n_r}\times{sin\theta_r}$

Where,  

${\theta_i}$  is the angle of incidence  ( 14.0° )

${\theta_r}$ is the angle of refraction  ( ? )

${n_r}$ is the refractive index of the refraction medium  (n=1.46)

${n_i}$ is the refractive index of the incidence medium (n=1.27)

Hence,  

$1.27\times {sin14.0^0}={1.46}\times{sin\theta_r}$

Angle of refraction = $sin^{-1}0.2104$ = 12.15°

Answer 2

Answer:

M

Explanation: