Answer:
5923.7 Pa/m
Explanation:
radius of capillary tube, r = 0.514 x 10^-3 m
Volume of flow, V = 7.06 cm^3/min = 1.176 x 10^-7 m^3/s
viscosity, η = 0.00138 Pa s
By use of Poiseuillie's law
[tex]V = \frac{\pi P\timesr^{4}}{8\eta\times l}[/tex]
Where, V be the volume flow per second and l be the length of the tube
So, pressure gradient
[tex]\frac{P}{l} = \frac{8\eta V}}{\pi r^{4}}[/tex]
[tex]\frac{P}{l} = \frac{8 \times 0.00138 \times 1.176 \times 10^-7}}{3.14 \times 0.514^{4} \times 10^{-12}}[/tex]
P/l = 5923.7 Pa/m