Question

If (2x-1) is a factor of the polynomial
P(x) = 2x^3-5x^2- Kx +3
find value of k.

Answer 1

Answer:

K = 4

Step-by-step explanation:

If (2x-1) is a factor, that means that when x = $\frac{1}{2}$, the function equals 0

$0 = 2(\frac{1}{2})^3 -5(\frac{1}{2})^2-K(\frac{1}{2})+3\\-3 = \frac{1}{4} -\frac{5}{4} -\frac{K}{2}\\ -3 = -1 - \frac{K}{2} \\-2 = \frac{-K}{2} \\K = 4$