Answer:
Pressure, [tex]P=29.6\times 10^5\ Pa[/tex]
Explanation:
It is given that,
Combined mass of the man and the chair, m = 95 kg
Radius of the leg of chair, r = 0.5 cm = 0.005 m
A large man sits on a four-legged chair with his feet off the floor. The force acting per unit area is called the pressure exerted.
[tex]P=\dfrac{F}{A}[/tex]
[tex]P=\dfrac{mg}{A}[/tex]
Area of 4 legs, A = 4 A
[tex]P=\dfrac{mg}{4\pi r^2}[/tex]
[tex]P=\dfrac{95\times 9.8}{4\pi (0.005)^2}[/tex]
[tex]P=29.6\times 10^5\ Pa[/tex]
So, the pressure each leg exert on the floor is [tex]29.6\times 10^5\ Pa[/tex]. Hence, this is the required solution.