Answer:
The standard deviation is calculated to be 2.886 in the given interval
Explanation:
Uniform distribution in an interval [a,b] is defined by the function
[tex]f(x)=\frac{1}{b-a}[/tex]
The variance of the distribution is given by
[tex]\sigma ^{2}=\frac{(b-a)^{2}}{12}[/tex]
Hence the standard deviation is given by
[tex]\sigma =\frac{(b-a)}{\sqrt{12}}[/tex]
Applying values we get
[tex]\sigma =\frac{6-(-4)}{\sqrt{12}}\\\\\sigma = \frac{10}{\sqrt{12}}=2.886[/tex]