Hey there!:
Given [ OH⁻ ] = 9.00 x 10⁻⁴
We know that : [H⁺ ] [OH⁻ ] = 1 x 10⁻¹⁴
Thus [H⁺ ] = ( 1 x 10⁻¹⁴ ) / ( 9.00 x 10⁻⁴ )
[ H⁺ ] = 1 x 10⁻¹¹ M
therefore:
pH = - log [ H⁺ ]
pH = - log [ 1 x 10⁻¹¹ ]
pH = 10.95
Therfore pH = 10.95
I hope this will help !