Answer: [tex]\pm1.753[/tex]
Step-by-step explanation:
Let [tex]\mu[/tex] be the population mean and [tex]\mu_0[/tex] be the actual mean price.
By considering the given information, we have
[tex]H_0: \mu=\mu_0\\\\H_a:\mu<\mu_0[/tex]
Given : Sample size : n= 16, which is a small sample so the test applied here is t-test.
Significance level : [tex]\alpha=0.05[/tex]
Degree of freedom =[tex]df=n-1=16-1=15[/tex]
By using the standard normal distribution t-table, the critical value for t-test will be :-
[tex]t_{(df, \alpha)}=t_{(15,0.05)}=\pm1.753[/tex]
Hence, the the critical value will be [tex]\pm1.753[/tex]