Question

A point charge q1 = -2.3 μC is located at the origin of a co-ordinate system. Another point charge q2 = 6.2 μC is located along the x-axis at a distance x2 = 9.9 cm from q1. 1) What is F12,x, the value of the x-component of the force that q1 exerts on q2?

Answer 1

Answer:

Explanation:

Force between two charges is given by coulomb's law as follows

F = $\frac{9\times10^9\times Q_1\times Q_2}{d^2}$

Where Q₁ and Q₂ are two adjescent charges at distance d.

Putting the given values in the equation we have

=$[tex]\frac{9\times10^9\times 2.3\times10^{-6}\times 6.2\times 10^{-6}}{(9.9\times10{-2})^2}$[/tex]

= 13.1 N

This will be attractive in nature so it will act in - ve x- direction.