Answer:
[tex][12.1175 , 18.4825][/tex]
Step-by-step explanation:
An ([tex]1-\alpha[/tex])% interval confidence for the population average, based on a sample of n individuals is given by:
[tex][\hat x - T_{\alpha /2} \sqrt{\frac{S^{2}}{n} } , \hat x + T_{\alpha /2} \sqrt{\frac{S^{2}}{n}} ][/tex], where [tex][\hat x[/tex] is the sample means, [tex][ S^{2}[/tex] is the sample standard deviation, [tex][T_{\alpha /2}[/tex] is the quantile value of the distribution T with [tex](n-1)[/tex] degrees of freedom and n is the sample size. thus,
[tex][\hat x - T_{\alpha /2} \sqrt{\frac{S^{2}}{n} } , \hat x + T_{\alpha /2} \sqrt{\frac{S^{2}}{n}} ] = [15.3 - 2.4334\sqrt{\frac{46.24}{20} } , 15.3 + 2.4334\sqrt{\frac{46.24}{20} } ] =[12.1175 , 18.4825][/tex]