Answer:
see explanation
Step-by-step explanation:
let ∠BCE = x then ∠ECD = 5x - 6 and
∠BCE + ∠ECD = ∠BCD, substitute values
x + 5x - 6 = 162, that is
6x - 6 = 162 ( add 6 to both sides )
6x = 168 ( divide both sides by 6 )
x = 28
Hence
∠BCE = x = 28°
∠ECD = 5x - 6 = (5 × 28) - 6 = 140 - 6 = 134°
Answer:
m∠BCE = 28º and m∠ECD=134º
Step-by-step explanation:
Consider the provided figure.
From the figure it can observed that
m∠BCD= m∠ECD+ m∠BCE
It is given that m∠ECD is six less than five times m∠BCE, and m∠BCD = 162º.
Let the m∠BCE is xº then the m∠ECD can be written as:
m∠ECD=5x-6
Now substitute the value of m∠ECD and m∠BCE in above equation.
m∠BCD= 5x-6+ x
As we know m∠BCD = 162º
Thus,
162= 5x-6+ x
162+6= 6x
168= 6x
x=28
Thus, the m∠BCE = 28º
Now substitute the value of x in m∠ECD=5x-6
m∠ECD=5(28)-6
m∠ECD=140-6
m∠ECD=134º
Hence, the m∠BCE = 28º and m∠ECD=134º
