Answer:
Step-by-step explanation:
PX + XQ = PQ
5x -3 + 13 = 40
5x = 30 . . . . . . . . subtract 10
x = 6 . . . . . . . . . . divide by 5
You can find XP either from its algebraic expression or from its sum with XQ.
XP + XQ = PQ
XP + 13 = 40 . . . fill in given values
XP = 27 . . . . . . . subtract 13
Also
XP = 5x -3 = 5(6) -3
XP = 27