Question

a puck moves 2.35 m/s in a -22.0 direction. A hockey stick pushes it for 0.125s, changing its velocity to 6.42m/s in a 50.0 direction. what was the magnitude of the accerlation

Answer 1

Answer:

  48.9 m/s²

Explanation:

The acceleration is given by ...

  a = (change in velocity)/(time)

  = ((final velocity) - (initial velocity))/time

  = ((6.42∠50° - 2.35∠-22°) m/s)/(0.125 s)

  ≈ (6.12∠71° m/s)/(0.125 s)

  ≈ 48.9∠71° m/s²

The magnitude of the average acceleration was 48.9 m/s².