Respuesta :

Answer:

m∠FJH=60°

Step-by-step explanation:

The complete question is

JG bisects FJH, FJG= (2x + 4)° and GJH = (3x -9)°  

What is FJH

we know that

m∠FJH=m∠FJG+m∠GJH -----> equation A

If ray JG is an angle bisector of ∠FJH

then

m∠FJG=m∠GJH -----> equation B

substitute the given values in equation B and solve for x

(2x + 4)°=(3x -9)°

3x-2x=4+9

x=13

Find the measure of angle FJH

m∠FJH=(2x + 4)°+(3x -9)°

substitute the value of x

m∠FJH=(2(13) + 4)°+(3(13) -9)°

m∠FJH=(30)°+(30)°

m∠FJH=60°

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